Mg\(_2\) + 2HCI\(_{(aq)}\) → MgCI\(_{2(g)}\) + H\(_{2(g)}\).

From the equation above what mass of hydrogen would be produced if 12.0 g of magnesium reacted completely with dilute hydrochloric acid? (H = 1, Mg = 24)

  • A 1.0g
  • B 2.0g
  • C 6.0g
  • D 12.0g
  • E 24.0g
waec 1994chemistry

The correct answer is A. 1.0g

Mg\(_2\) + 2HCI\(_{(aq)}\) → MgCI\(_{2(g)}\) + H\(_{2(g)}\).

24g Mg reacts with 2g H

1g Mg = \(\frac{2}{24}\)g H

12g Mg = \(\frac{2}{24} \times 12\)g H

= 1g H.

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