One mole of a compound M(HCO3)2 has a mass of 162g. Calculate the relative atomic mass of M. [H = 1, C =12, O = 16]

  • A 122
  • B 101
  • C 53
  • D 40
waec 1999chemistry

The correct answer is D. 40

One of the mole of M(HCO3)2 = 162g; M +(1 + 12 + 16 x 3) x 2 = 162; M +122 = 162,:. M = 162 - 122 = 40g

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