What is the oxidation number of chromium in K2CrO4?

  • A +1
  • B +2
  • C +4
  • D +6
waec 2007chemistry

The correct answer is D. +6

K2CrO4 (O.N of K) X 2 + O.N of Cr + (O.N of oxygen) X 4 = 0

1 X 2 + X + -2 X 4 = 0

2 + x + -8 = 0

2 + x - 8 = 0

x = 8 - 2 = + 6

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