Atom \(^{234} _{88} Q\) decay by alpha emission to give an atom R. The atomic number and mass number of atom R are respectively

  • A 86 and 230
  • B 87 and 234
  • C 88 and 233
  • D 90 and 238
waec 2008chemistry

The correct answer is A. 86 and 230

\(^{234} _{88} Q \to R + ^4 _2 He\)

\(\therefore R = ^{234 - 4} _{88 - 2} R\)

= \(^{230} _{86} R\)

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