Consider the reaction represented by the question below: KOH(aq) + HCI(aq) → KCI(aq) + H2O(l) What volume of 0.25 mol dm-3 KOH would be required to completely neutralize 40 cm3 of 0.10 mol dm -3 HCI?

The answer is D. 16cm3.

Consider the reaction represented by the question below: KOH(aq) + HCI(aq) → KCI(aq) + H2O(l) What volume of 0.25 mol dm-3 KOH would be required to completely neutralize 40 cm3 of 0.10 mol dm -3 HCI?

Consider the reaction represented by the question below: KOH_(aq) + HCI_(aq) → KCI_(aq) + H₂O_(l) What volume of 0.25 mol dm^-3 KOH would be required to completely neutralize 40 cm³ of 0.10 mol dm ^-3 HCI?

A 40 cm³
B 32cm³
C 24cm³
D 16cm³

waec 2008 chemistry

The correct answer is D. 16cm³

No explanation given

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