The oxidation number of sulphur in Fe2(SO4)3 is

  • A +2.
  • B +3
  • C +4.
  • D +6.

The correct answer is D. +6.

Fe2(SO4)3 = 0

(+3 x 2) 9 3x + (-2 x 4 x 3) = 0

+6 + 3x -24 = 0

+3x - 18 = 0

3 x = 18

x = 18/3 = +6

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