The oxidation number of sulphur in Fe2(SO4)3 is
The correct answer is D. +6.
Fe2(SO4)3 = 0
(+3 x 2) 9 3x + (-2 x 4 x 3) = 0
+6 + 3x -24 = 0
+3x - 18 = 0
3 x = 18
x = 18/3 = +6
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