Consider the reaction represented by the following equation: Na2CO3(aq) + 2HCl(aq) \(\longrightarrow\) 2NaCl(aq) + H2O(l) + CO2(g) . What volume of 0.02 mol dm-3 Na2CO3(aq) would be required to completely neutralize 40 cm3 of 0.10 mol dm-3 HCl(aq)?

The answer is B. 100 cm3.

Consider the reaction represented by the following equation: Na2CO3(aq) + 2HCl(aq) \(\longrightarrow\) 2NaCl(aq) + H2O(l) + CO2(g) . What volume of 0.02 mol dm-3 Na2CO3(aq) would be required to completely neutralize 40 cm3 of 0.10 mol dm-3 HCl(aq)?

Consider the reaction represented by the following equation: Na₂CO_3(aq) + 2HCl_(aq) \(\longrightarrow\) 2NaCl_(aq) + H₂O_(l) + CO_2(g) . What volume of 0.02 mol dm^-3 Na₂CO_3(aq) would be required to completely neutralize 40 cm³ of 0.10 mol dm^-3 HCl_(aq)?

A 200 cm³
B 100 cm³
C 40 cm³
D 20 cm³

waec 2014 chemistry

The correct answer is B. 100 cm³

No explanation given

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