Consider the following equation: Cr2O2-7(aq) + 14H+(aq) + 6e- → 2Cr3+(ag) + 7H2O(1). The oxidation number of chromium changes from

Consider the following equation: Cr₂O^2-_7(aq) + 14H⁺_(aq) + 6e^- → 2Cr³⁺_(ag) + 7H₂O₍₁₎. The oxidation number of chromium changes from

The correct answer is C. +6 to +3

No explanation given