On evaporation to dryness, 3503 of saturated solution of salt Z gave 55.5g of salt. What is the solubility of the salt? [Z = 101]

  • A 1.57 moldm-3
  • B 3.14 moldm-3
  • C 6.28 moldm-3
  • D 12.56 moldm-3
waec 2016chemistry

The correct answer is A. 1.57 moldm-3

Saturated solution = 3503

mass of salt Z in saturated solution = 55.5g

Number of moles of salt = \(\frac{55.5}{101}\) = 0.55mole

3503 of solution contains 0.55mole

1000cm3 will contain \(\frac{1000 \times 0.55}{350}\) = 1.57mol/dm3

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