The number of oxygen molecules present in 16.0g of the gas is ______?

[Avogadro's number = 6.02 x 1023]

  • A 6.02 x 1022
  • B 6.02 x 1023
  • C 3.01 x 1023
  • D 1.51 x 1023
waec 2015chemistry

The correct answer is C. 3.01 x 1023

1 mole = Molar mass of gas = Avogadros number

32g of O2 = 6.02 x 1023

16g of O2 = x

x = \(\frac{16 \times 6.02 \times 10^23}{32}\) = 3.01 x 1023

Previous question Next question