If 60 g of M combines with 24 g of oxygen, what would the empirical formula of the oxide be?

  • A MO
  • B MO\(_{2}\)
  • C MO\(_{3}\)
  • D MO\(_{4}\)
waec 2022chemistry

The correct answer is C. MO\(_{3}\)

Data obtained from the question

M = 60 g

O = 24 g

Empirical formula =?

How to determine the empirical formula

Divide by their molar mass

M = 60÷120 = 0.5

O = 24 ÷16 = 1.5

Divide by the smallest

M = 0.5÷0.5 = 1

O = 1.5 ÷0.5 = 3

Thus, the empirical formula of the oxide is MO₃

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