A straight line 2x+3y=6, passes through the point (-1,2). Find the equation of the line.

  • A 2x-3y=2
  • B 2x-3y=-2
  • C 2x+3y=-4
  • D 2x+3y=4
waec 2017furthermathematics

The correct answer is D. 2x+3y=4

\(2x+3y = 6 \implies 3y = 6-2x\)

\(y = \frac{6}{3} - \frac{2x}{3}\) 

Parallel lines have the same gradient

\(\therefore\) Gradient of the line = \(\frac{-2}{3}\)

Line passes through (-1,2)

Equation: \(\frac{y-2}{x-(-1)} = \frac{y-2}{x+1} = \frac{-2}{3}\)

\(3y-6 = -2x-2 \implies 3y+2x = -2+6 =4\)

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