Simplify \(\frac{\sqrt{128}}{\sqrt{32} - 2\sqrt{2}}\)

  • A \(2\sqrt{2}\)
  • B \(3\sqrt{2}\)
  • C 3
  • D 4
waec 2017furthermathematics

The correct answer is D. 4

\(\sqrt{128}  = \sqrt{64\times2} = 8\sqrt{2}\)

\(\sqrt{32} = \sqrt{16\times2} = 4\sqrt{2}\)

Simplifying, we have \(\frac{8\sqrt{2}}{4\sqrt{2} - 2\sqrt{2}} = \frac{8\sqrt{2}}{2\sqrt{2}}\)

= 4

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