If P = \({n^{2} + 1: n = 0,2,3}\) and Q = \({n + 1: n = 2,3,5}\), find P\(\cap\) Q.

  • A {5, 10}
  • B {4, 6}
  • C {1, 3}
  • D { }
waec 2017furthermathematics

The correct answer is D. { }

\(P = {n^{2} + 1: n = 0,2,3} \therefore P = {1, 5,10}\)

\(Q = {n + 1: n = 2,3,5} \therefore Q = {3, 4, 6}\)

\(P \cap Q = { }\)

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