The midpoint of M(4, -1) and N(x, y) is P(3, -4). Find the coordinates of N.

  • A (2, -3)
  • B (2, -7)
  • C (-1, -3)
  • D (-10, -7)

The correct answer is B. (2, -7)

Given \(M(4, -1)\) and \(N(x, y)\) with midpoint \(P(3, -4)\).

\(\implies \frac{4 + x}{2} = 3; \frac{-1 + y}{2} = -4\)

\(\therefore x = 2; y = -7\)

N = (2, -7)

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