Given n = 3, evaluate \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!}\)

  • A \(12\)
  • B \(2\frac{1}{2}\)
  • C \(2\)
  • D \(\frac{11}{24}\)
waec 2016furthermathematics

The correct answer is D. \(\frac{11}{24}\)

n = 3, \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!} = \frac{1}{(3-1)!} - \frac{1}{(3+1)!}\)

= \(\frac{1}{2} - \frac{1}{24} = \frac{12 -1}{24}\)

= \(\frac{11}{24}\)

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