Find the minimum value of \(y = 3x^{2} - x - 6\).

  • A \(-6\frac{1}{6}\)
  • B \(-6\frac{1}{12}\)
  • C \(-6\)
  • D \(0\)
waec 2016furthermathematics

The correct answer is B. \(-6\frac{1}{12}\)

\(3x^{2} - x - 6 = y\)

\(a = 3, b = -1, c = -6\)

Minimum value of x = \(\frac{-b}{2a} = \frac{-(-1)}{6} = \frac{1}{6}\)

\(y(\frac{1}{6}) = 3(\frac{1}{6}^{2}) - \frac{1}{6} - 6 = -6\frac{1}{12}\)

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