If \(\log_{9} 3 + 2x = 1\), find x.

  • A \(\frac{-1}{2}\)
  • B \(\frac{-1}{4}\)
  • C \(\frac{1}{4}\)
  • D \(\frac{1}{2}\)
waec 2011furthermathematics

The correct answer is C. \(\frac{1}{4}\)

\(\log_{9} 3 = \log_{9} (9^{\frac{1}{2}}) = \frac{1}{2}\log_{9} 9 = \frac{1}{2}\)

\(\frac{1}{2} + 2x = 1 \implies 2x = \frac{1}{2}\)

\(x = \frac{1}{4}\)

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