The probability that Kofi and Ama hit a target in a shooting competition are \(\frac{1}{6}\) and \(\frac{1}{9}\) respectively. What is the probability that only one of them hit the target?

  • A \(\frac{1}{54}\)
  • B \(\frac{13}{54}\)
  • C \(\frac{20}{27}\)
  • D \(\frac{41}{54}\)
waec 2011furthermathematics

The correct answer is B. \(\frac{13}{54}\)

P(only one hit target) = P(Kofi not Ama) + P(Ama not Kofi)

P(Kofi not Ama) = P(Kofi and Ama') = \(\frac{1}{6} \times \frac{8}{9} = \frac{8}{54}\)

P(Ama not Kofi) = P(Ama and Kofi') = \(\frac{1}{9} \times \frac{5}{6} = \frac{5}{54}\)

P(only one hit target) = \(\frac{8}{54} + \frac{5}{54} = \frac{13}{54}\)

Previous question Next question