In how many ways can 3 prefects be chosen out of 8 prefects?

  • A 6
  • B 24
  • C 56
  • D 336
waec 2011furthermathematics

The correct answer is C. 56

= \(^{8}C_{3} = \frac{8!}{(8 - 3)! 3!}\)

= \(\frac{8 \times 7 \times 6}{3 \times 2}\)

= 56 ways

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