If \(\sin x = -\sin 70°, 0° < x < 360°\), determine the two possible values of x.

  • A 110°, 250°
  • B 110°, 290°
  • C 200°, 250°
  • D 250°, 290°
waec 2010furthermathematics

The correct answer is D. 250°, 290°

The value of the sine of an angle is negative in the third and fourth quadrant. Hence options A and B are not the options.

\(\sin 250 = -\sin (250 - 180) = - \sin 70\)

\(\sin 290 = - \sin (360 - 290) = - \sin 70\)

Previous question Next question