Yomi was asked to label four seats S, R, P, Q. What is the probability he labelled them in alphabetical order?

  • A \(\frac{1}{24}\)
  • B \(\frac{1}{6}\)
  • C \(\frac{2}{13}\)
  • D \(\frac{1}{4}\)
waec 2010furthermathematics

The correct answer is A. \(\frac{1}{24}\)

The number of arrangements for the 4 letters = \(^{4}P_{4} = \frac{4!}{(4 - 4)!}\)

\(4! = 24\)

Alphabetical order is just 1 of the arrangements for the letters 

= \(\frac{1}{24}\)

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