For what range of values of x is x\(^2\) - 2x - 3 ≤ 0

  • A {x: -1 ≤ x ≤ 3}
  • B { x: -3 ≤ x ≤ 1}
  • C { x: -3 ≤ x ≤ -1}
  • D { x: 1 ≤ x ≤ 3}

The correct answer is A. {x: -1 ≤ x ≤ 3}

Let  x\(^2\) - 2x - 3 = 0;

(x+1)(x-3) = 0

 The zeros of the function are x = -1 and 3

The solution set is { x: -1 â‰¤ x â‰¤ 3}

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