Simplify \(\frac{1}{3}\) log8 + \(\frac{1}{3}\) log 64 - 2 log6

  • A log \(\frac{2}{7}\)
  • B log 2
  • C log \(\frac{2}{9}\)
  • D log 9

The correct answer is C. log \(\frac{2}{9}\)

\(\frac{1}{3}\) log8 + \(\frac{1}{3}\) log 64 - 2 log6

= log 2 + log 4 - log 36

= log \(\frac{8}{36}\)

= log \(\frac{2}{9}\)

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