A committee consists of 6 boys and 4 girls. In how many ways can a sub-committee consisting of 3 boys and 2 girls be formed if one particular boy and one particular girl must be on the sub-committee?

  • A 120
  • B 80
  • C 56
  • D 30
waec 2021furthermathematics

The correct answer is A. 120

The required committee can be formed in 

\(^{6}C_{3}\) * \(^{4}C_{2}\) = \(\frac{6 * 5 * 4}{3 * 2 * 1}\) * \(\frac{4 * 3}{2 * 1}\)

20 * 6 = 120ways

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