Evaluate \(∫^0_{-1}\) (x + 1)(x - 2) dx

  • A 7/6
  • B 5/6
  • C -5/6
  • D -7/6
waec 2022furthermathematics

The correct answer is D. -7/6

\(∫^0_{-1}\) (x + 1)(x - 2) dx = \(∫^0_{-1}\) \(x^2 - x - 2\) dx Integrated \(x^2 - x - 2\) = \(\frac{x^3}{3} - \frac{x^2}{2} -2\)
= (0 - 0 - 0) - ( -1 3 - 1 2 + 2)
= 0 - ( 7 6 ) = -7 6
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