Given that P = (-4, -5) and Q = (2,3), express →PQ in the form (k,θ). where k is the magnitude and θ the bearing.

  • A (10 units, 053º)
  • B (9 units, 049º)
  • C (10 units, 037º)
  • D (9 units, 027º)

The correct answer is A. (10 units, 053º)

|→PQ| = √[(2-(-4))\(^2\) + (3-(-5))\(^2\)]

|→PQ| = √\(6^2 + 8^2\)

|→PQ| = √100

|→PQ| = 10units

tanθ = \(\frac{3--5}{2--4}\)

tanθ = \(\frac{4}{3}\) 

θ = \(tan^{-1}\frac{4}{3}\)

= 53º

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