The gradient of a function at any point (x,y) 2x - 6. If the function passes through (1,2), find the function.

  • A x\(^2\) -  6x - 5
  • B x\(^2\) -  6x + 5
  • C x\(^2\) -  6x - 3
  • D x\(^2\) -  6x + 7

The correct answer is D. x\(^2\) -  6x + 7

dy/dx = 2x - 6

y = ∫ 2x - 6

y = \(\frac{2x^2}{2} - 6 + c\)

y = x\(^2\) - 6x + c

passes through (1,2)

2 = 1\(^2\) - 6(1) + c

2 = 1 - 6 + c

c = 7

y = x\(^2\) - 6x + c

y = x\(^2\) -  6x + 7

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