The diagram shows a circle centre O. if <STR = 29 and <RST = 45, calculate the value of <STO

  • A 12\(^o\)
  • B 15\(^o\)
  • C 29\(^o\)
  • D 34\(^o\)

The correct answer is A. 12\(^o\)

SRT = 180 - (46 + 29) sum of < s in a

= 180 - 75

= 105

SOT = 2 x 46 < at the centre is twice all the circle = 92

RTO = 180 - (96 + 43)

= 41

STO = 41 - 29

= 12\(^o\)

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