In the diagram, NQ//TS, <RTS = 50\(^o\) and <PRT = 100\(^o\). Find the value of <NPR

  • A 110\(^o\)
  • B 130\(^o\)
  • C 140\(^o\)
  • D 150\(^o\)

The correct answer is B. 130\(^o\)

< TSR = 180 - (80 + 50)

= 180 - (130)

= 50\(^o\)

< QPR = < TSR corresponding < s

< NPR + QPR = < NPR

180\(^o\) - < QPR = < NPR

180\(^o\) - 50 = < NPR

< NPR = 130\(^o\)

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