Find the range of values of x for which\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\)

  • A x > 4
  • B x > -4
  • C x < 4
  • D x < -4
waec 2004mathematics

The correct answer is D. x < -4

\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\\

\frac{3(x+2)-4(x+1)>6}{12}; 3x + 6 – 4x – 4 > 6\

-x +2>6; -x > 4; x < -4\)

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