A fair die is tossed once, what is the probability of obtaining neither 5 or 2

  • A \(\frac{5}{6}\)
  • B \(\frac{2}{3}\)
  • C \(\frac{1}{2}\)
  • D \(\frac{1}{6}\)
waec 2005mathematics

The correct answer is B. \(\frac{2}{3}\)

Probability of obtaining a 5 is P(5)=\(\frac{1}{6}\)

Probability of obtaining a 2 is P(2)=\(\frac{1}{6}\)

Probability of obatining either 2 or 5 = P(2∪5) = \(\frac{2}{6}\)

Probability of obtaining neither 5 or 2 = \(1 - \frac{2}{6}=\frac{4}{6}=\frac{2}{3}\)

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