Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the value of k

  • A -4
  • B -2
  • C -1
  • D \(-\frac{1}{4}\)
waec 2005mathematics

The correct answer is A. -4

Substituting for x in the equation

\(2(2)^2 + (k+2)2+k = 0 \Rightarrow 8 +2k + 4 + k =0 \Rightarrow 3k =-12; k=-4\)

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