Simplify: \(\frac{2}{3xy} - \frac{3}{4yz}\)

  • A \(\frac{2-x}{12xyz}\)
  • B \(\frac{2z-3x}{12xyz}\)
  • C \(\frac{4z-3x}{12xyz}\)
  • D \(\frac{8z-9x}{12xyz}\)
waec 2005mathematics

The correct answer is D. \(\frac{8z-9x}{12xyz}\)

\(\frac{2}{3xy} - \frac{3}{4yz} = \frac{2(4)-3(3x)}{12xyz} = \frac{8z-9x}{12xyz}\)

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