The angle of elevation of the top of a cliff 15 meters high from a landmark is 60o. How far is the landmark from the foot of the cliff? Leave your answer in surd form

  • A \(15\sqrt{3}m\)
  • B \(15\sqrt{2}m\)
  • C \(10\sqrt{3}m\)
  • D \(5\sqrt{3}m\)

The correct answer is A. \(15\sqrt{3}m\)

Tan 60º = \(\frac{15}{x}\}

cross multiply:

x = \(\frac{15}{√3}\}

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