\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table above satisfies the relation y = k\(\sqrt{x}\), where k is a positive constant. Find the value of K.

\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table above satisfies the relation y = k\(\sqrt{x}\), where k is a positive constant. Find the value of K.

A 0.5
B 1
C 1.5
D 2

waec 2006 mathematics

The correct answer is A. 0.5

y = k\(\sqrt{x}\) when y = 1, x = 4

k = \(\frac{y}{\sqrt{x}}\)

= \(\frac{1}{\sqrt{4}}\)

= \(\frac{1}{2}\)

= 0.5

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