A machine valued at N20,000 depreciates by 10% every year. What will be the value of the machine at the end of two years?

  • A N16,200
  • B N1,4,200
  • C 12,000
  • D 8000.
waec 2006mathematics

The correct answer is A. N16,200

D = P(I - \(\frac{R}{100}\))n where P = N20,000; R = 10%, n = 2

D = 20,000(I - \(\frac{10}{100}\))2

= 20000(0.9)2

20,000 x 0.81 = N16,200

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