Simplify \(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\)

  • A \(\frac{x-1}{x-3}\)
  • B \(\frac{-2}{x+3}\)
  • C \(\frac{x-1}{x+3}\)
  • D \(\frac{4x}{x^2-9}\)
waec 2000mathematics

The correct answer is B. \(\frac{-2}{x+3}\)

\(\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\\

\frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}\\

\frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}\\

\frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3}\)

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