Evaluate \((20_{three})^2 - (11_{three})^2\) in base three

  • A 101
  • B 121
  • C 202
  • D 2020
waec 2001mathematics

The correct answer is C. 202

\((20_{three})^2 - (11_{three})^2\)

= \((20_{3} - 11_{3})(20_{3} + 11_{3})\)

= \((2_{3})(101_{3})\)

= \(202_{3}\)

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