If 3x\(^o\) 4(mod 5), find the least value of x

  • A 1
  • B 2
  • C 3
  • D 4
waec 2018mathematics

The correct answer is C. 3

3x \(\equiv\) 4(mod 5)

In modulo 5, multiples of 5 that give solution to the given equation are 5, 20, 35, 50,... but 5 will yield the leaast value of x.

Thus; 3x = 4 + 5 = 9

x = \(\frac{9}{3}\)

x = 3

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