The solution of x + 2 \(\geq\) 2x + 1 is illustrated

  • A i
  • B ii
  • C iii
  • D iv

The correct answer is A. i

x + 2 \(\geq\) 2x + 1

x - 2x \(\geq\) 1 - 2

-x \(\geq\) -1

\(\frac{-x}{-1}\) \(\geq\) \(\frac{-1}{-1}\)

x \(\leq\) 1

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