Given that Y is 20cm on a bearing of 300\(^o\) from x, how far south of y is x?

  • A 10cm
  • B 15cm
  • C 25cm
  • D 30cm

The correct answer is A. 10cm

In \(\bigtriangleup\)YSC, sin 30\(^o\) = \(\frac{YS}{20}\)

|YS| = 20 sin 30\(^o\)

= 20 x 0.5

10m

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