Solve: - \(\frac{1}{4}\) < \(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\)

  • A -\(\frac{5}{9}\) < x <\(\frac{8}{9}\)
  • B -\(\frac{8}{9}\) < x <\(\frac{7}{9}\)
  • C -\(\frac{8}{9}\) < x <\(\frac{5}{9}\)
  • D -\(\frac{7}{9}\) < x <\(\frac{8}{9}\)
waec 2017mathematics

The correct answer is A. -\(\frac{5}{9}\) < x <\(\frac{8}{9}\)

\(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\); \(\frac{3}{4}\) (3x - 2) > - \(\frac{1}{4}\)

3(3x - 2) < 2; 3(3x - 2) > -1

9x - 6 < 2; 9x - 6 > -1

9x < 8; 9x > 5

x < \(\frac{5}{9}\); x > \(\frac{8}{9}\)

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