The roots of a quadratic equation are \(\frac{-1}{2}\) and \(\frac{2}{3}\). Find the equation.

  • A \(6x^2 - x + 2 = 0\)
  • B \(6x^2 - x - 2 = 0\)
  • C \(6x^2 + x - 2 = 0\)
  • D \(6x^2 + x + 2 = 0\)
waec 2017mathematics

The correct answer is B. \(6x^2 - x - 2 = 0\)

(x + \(\frac{1}{2}\)) (n - \(\frac{2}{3}\))

\(x^2 - \frac{2}{3^x} + \frac{x}{2} - \frac{1}{3}\)

\(6x^2 - 4n + 3n - 2 = 0\)

\(6x^2 - x - 2 = 0\)

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