If m : n = 2 : 1, evaluate \(\frac{3m^2 - 2n^2}{m^2 + mn}\)

  • A \(\frac{4}{3}\)
  • B \(\frac{5}{3}\)
  • C \(\frac{3}{4}\)
  • D \(\frac{3}{5}\)
waec 2019mathematics

The correct answer is B. \(\frac{5}{3}\)

m = 2, n = 1

\(\frac{3m^2 - 2n^2}{m^2 _ mn}\)

= \(\frac{3(2)^2 - 2(1)^2}{2^2 + 2(1)}\)

= \(\frac{12 - 2}{4 + 2} = \frac{10}{6}\)

= \(\frac{5}{3}\)

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