In XYZ, |YZ| = 32cm, < YXZ 53\(^o\) and XZY = 90\(^o\). Find, correct to the nearest centimetre, |XZ|

  • A 31 cm
  • B 25 cm
  • C 20 cm
  • D 13 cm
waec 2019mathematics

The correct answer is B. 25 cm

Tan 52\(^o\) = \(\frac{32}{\text{|XZ|}}\)

|XZ| = \(\frac{32}{Tan 52^o}\)

= 25cm

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