If 2\(^{a}\) = \(\sqrt{64}\) and \(\frac{b}{a}\) = 3, evaluate a\(^2 + b^{2}\)

  • A 250
  • B 160
  • C 90
  • D 48
waec 2019mathematics

The correct answer is C. 90

2\(^a\) = \(\sqrt{64}\)

2\(^a\) = 8

2\(^a\) = 2\(^3\)

a = 3

b = 3\(^a\)

b = 3 x 3 = 9

a\(^2\) + b\(^2\) = 3\(^2\) + 9\(^2\) 

= 9 + 81 = 90

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