The interior angles of a polygon are 3x\(^o\), 2x\(^o\), 4x\(^o\), 3x\(^o\) and 6\(^o\). Find the size of the smallest angle of the polygon.

  • A 80\(^o\)
  • B 60\(^o\)
  • C 40\(^o\)
  • D 30\(^o\)
waec 2019mathematics

The correct answer is B. 60\(^o\)

3\(x^o\) + 2\(x^o\) + 4\(x^o\) + 3\(x^o\) + 6\(x^o\) = 540\(x^o\)

\(\frac{18x^o}{18} = \frac{540^o}{18}\)

\(x^o\) = 30\(^o\)

Smallest angle = 2 x 30\(^o\) = 60\(^o\)

Previous question Next question