If 101\(_{\text{two}}\) + 12y = 3.3\(_{\text{five}}\). Find the value of y

  • A 8
  • B 7
  • C 6
  • D 5

The correct answer is C. 6

012 + 01 = 01

101\(_2\) + 12\(_y\) = 2.3\(_5\)

1 x 2\(^o\) + 0 x 2\(^o\) + 1 x2\(^2\) + 1 x y\(^o\) + 2 x y\(^1\) = 3 x 5\(^o\) + 3 x 5\(^1\)

1 + 4 + 1 + 2y = 3 + 15

6 + 2y = 18 

2y = 18 - 6

\(\frac{2y}{2} = \frac{12}{2}\)

y = 6

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