Express 1 + 2 log10\(^3\) in the form log10\(^9\)

  • A log10\(^{90}\)
  • B log10\(^{19}\)
  • C log10\(^{9}\)
  • D log10\(^{6}\)
waec 2020mathematics

The correct answer is A. log10\(^{90}\)

1 + 2log\(_{10}^3\)

= log\(_{10}^{10} + log_{10}^{3^2}\)

= log\(_{10}^{10} + log_{10}^{9}\)

= log\(_{10}^{10 \times 90}\) = log\(_{10}^{90}\)

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